4a-4a[5-2(a+2)]=

Solution for 4a-4a[5-2(a+2)]= equation:

Simplifying
4a + -4a[5 + -2(a + 2)] = 0

Reorder the terms:
4a + -4a[5 + -2(2 + a)] = 0
4a + -4a[5 + (2 * -2 + a * -2)] = 0
4a + -4a[5 + (-4 + -2a)] = 0

Combine like terms: 5 + -4 = 1
4a + -4a[1 + -2a] = 0
4a + [1 * -4a + -2a * -4a] = 0
4a + [-4a + 8a2] = 0

Combine like terms: 4a + -4a = 0
0 + 8a2 = 0
8a2 = 0

Solving
8a2 = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Divide each side by '8'.
a2 = 0

Simplifying
a2 = 0

Take the square root of each side:
a = {0}